Home/
Competitive Exams/
JEE Main & Advanced/
Chemistry/
Aldehydes, Ketones and Carboxylic Acids/
Question 790011
JEE Chemistry · Hard

Aldehydes, Ketones and Carboxylic Acids: JEE Advanced MCQ

Solve this quality-checked JEE multiple-choice question, then review the correct answer and explanation.

Timer-based practiceDetailed answer reviewMobile-friendly flow
JEE AdvancedHardQuestion 790011

Question

Rosenmund reduction of acid chloride (RCOCl + H₂, Pd/BaSO₄) gives:
  1. A
    Aldehyde (RCHO)
    Correct
  2. B
    Carboxylic acid
  3. C
    Alcohol
  4. D
    Alkane

Correct answer

Aldehyde (RCHO)

Explanation

Rosenmund reduction: RCOCl + H₂ → RCHO (aldehyde). The poisoned catalyst (Pd/BaSO₄) prevents further reduction of the aldehyde to alcohol. Used for preparing aldehydes from acid chlorides.

Review Aldehydes, Ketones and Carboxylic Acids notesStart timed chapter practice