JEE Chemistry · Hard

Aldehydes, Ketones and Carboxylic Acids: Mixed MCQ

Solve this quality-checked JEE multiple-choice question, then review the correct answer and explanation.

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MixedHardQuestion 790014

Question

The decarboxylation of RCOONa by sodalime (NaOH + CaO) on heating gives:
  1. A
    Alkane (R−H)
    Correct
  2. B
    Alkene
  3. C
    Alcohol
  4. D
    CO₂ only

Correct answer

Alkane (R−H)

Explanation

Dry distillation of sodium salt of carboxylic acid with CaO (soda lime): RCOONa + NaOH → R−H + Na₂CO₃. The decarboxylation removes one carbon as CO₂, giving an alkane with one fewer carbon than the acid.