Rydberg EquationMediumQuestion 600205
Question
The wavelength of light emitted when hydrogen electron falls from n=4 to n=2 (Rydberg constant R = 1.097×10⁷ m⁻¹) is:
- A486 nmCorrect
- B656 nm
- C434 nm
- D410 nm
Correct answer
486 nm
Explanation
1/λ = R(1/4 − 1/16) = R×(3/16). λ = 16/(3R) = 16/(3×1.097×10⁷) ≈ 4.86×10⁻⁷ m = 486 nm (Hβ line, blue-green).