de BroglieMediumQuestion 600207
Question
The de Broglie wavelength of a particle with momentum p is:
- Aλ = h/pCorrect
- Bλ = hp
- Cλ = h/mv²
- Dλ = p/h
Correct answer
λ = h/p
Explanation
de Broglie wavelength: λ = h/p = h/(mv). Gives wave character to all matter particles.