de BroglieHardQuestion 600225
Question
An electron accelerated through potential V volts has de Broglie wavelength λ = 12.27/√V Å. At V = 100 V, λ is:
- A1.227 ÅCorrect
- B0.1227 Å
- C12.27 Å
- D122.7 pm
Correct answer
1.227 Å
Explanation
λ = 12.27/√100 = 12.27/10 = 1.227 Å = 122.7 pm. This formula is derived from KE = eV and λ = h/√(2meV).