JEE Chemistry · Hard

Atomic Structure: de Broglie MCQ

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de BroglieHardQuestion 600225

Question

An electron accelerated through potential V volts has de Broglie wavelength λ = 12.27/√V Å. At V = 100 V, λ is:
  1. A
    1.227 Å
    Correct
  2. B
    0.1227 Å
  3. C
    12.27 Å
  4. D
    122.7 pm

Correct answer

1.227 Å

Explanation

λ = 12.27/√100 = 12.27/10 = 1.227 Å = 122.7 pm. This formula is derived from KE = eV and λ = h/√(2meV).