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Question 600236
JEE Chemistry · Medium

Atomic Structure: Photoelectric MCQ

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PhotoelectricMediumQuestion 600236

Question

The threshold frequency for a metal is ν₀. If light of frequency 2ν₀ hits it, the maximum KE of emitted electrons is:
  1. A
    hν₀
    Correct
  2. B
    2hν₀
  3. C
    h(2ν₀ − ν₀) = hν₀
  4. D
    3hν₀

Correct answer

hν₀

Explanation

KE_max = hν − hν₀ = h(2ν₀) − hν₀ = hν₀.

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