Wave-particleHardQuestion 600243
Question
An electron and a proton have the same de Broglie wavelength. The ratio of their kinetic energies KE_e/KE_p is:
- Amp/meCorrect
- Bme/mp
- C1
- D(mp/me)²
Correct answer
mp/me
Explanation
Same λ → same momentum p. KE = p²/(2m). So KE_e/KE_p = mp/me ≈ 1836.