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Question 870010
JEE Chemistry · Hard

Biomolecules and Polymers: JEE Advanced MCQ

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JEE AdvancedHardQuestion 870010

Question

The number of chiral centres in glucose (open-chain aldohexose) is:
  1. A
    4
    Correct
  2. B
    3
  3. C
    5
  4. D
    2

Correct answer

4

Explanation

Open-chain glucose: CHO−CH(OH)−CH(OH)−CH(OH)−CH(OH)−CH₂OH. Carbons 2, 3, 4, 5 each have 4 different substituents → 4 chiral centres. Maximum stereoisomers = 2⁴ = 16 (8 pairs of enantiomers, 8 D-aldohexoses and 8 L-aldohexoses).

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