Home/
Competitive Exams/
JEE Main & Advanced/
Chemistry/
Chemical and Ionic Equilibrium/
Question 600402
JEE Chemistry · Easy

Chemical and Ionic Equilibrium: Kp and Kc MCQ

Solve this quality-checked JEE multiple-choice question, then review the correct answer and explanation.

Timer-based practiceDetailed answer reviewMobile-friendly flow
Kp and KcEasyQuestion 600402

Question

The relation between Kp and Kc is:
  1. A
    Kp = Kc(RT)^Δn
    Correct
  2. B
    Kp = Kc + Δn RT
  3. C
    Kp = Kc / (RT)^Δn
  4. D
    Kp = Kc always

Correct answer

Kp = Kc(RT)^Δn

Explanation

Kp = Kc(RT)^Δn where Δn = moles of gaseous products − moles of gaseous reactants. R = 0.0821 L·atm/mol·K.

Review Chemical and Ionic Equilibrium notesStart timed chapter practice