Kc calculationMediumQuestion 600407
Question
For H₂ + I₂ ⇌ 2HI, if [H₂] = [I₂] = 0.1 M and [HI] = 0.8 M at equilibrium, Kc is:
- A64Correct
- B8
- C0.8
- D32
Correct answer
64
Explanation
Kc = [HI]²/([H₂][I₂]) = (0.8)²/(0.1×0.1) = 0.64/0.01 = 64.
Solve this quality-checked JEE multiple-choice question, then review the correct answer and explanation.
Kc = [HI]²/([H₂][I₂]) = (0.8)²/(0.1×0.1) = 0.64/0.01 = 64.