KwEasyQuestion 600422
Question
The ionic product of water Kw at 25°C is:
- A10⁻⁷
- B10⁻¹⁴Correct
- C14
- D10⁷
Correct answer
10⁻¹⁴
Explanation
Kw = [H⁺][OH⁻] = 10⁻¹⁴ at 25°C. This means at neutral pH, [H⁺] = [OH⁻] = 10⁻⁷ M, giving pH = 7.
Solve this quality-checked JEE multiple-choice question, then review the correct answer and explanation.
Kw = [H⁺][OH⁻] = 10⁻¹⁴ at 25°C. This means at neutral pH, [H⁺] = [OH⁻] = 10⁻⁷ M, giving pH = 7.