JEE Chemistry · Easy

Chemical and Ionic Equilibrium: Kw MCQ

Solve this quality-checked JEE multiple-choice question, then review the correct answer and explanation.

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KwEasyQuestion 600422

Question

The ionic product of water Kw at 25°C is:
  1. A
    10⁻⁷
  2. B
    10⁻¹⁴
    Correct
  3. C
    14
  4. D
    10⁷

Correct answer

10⁻¹⁴

Explanation

Kw = [H⁺][OH⁻] = 10⁻¹⁴ at 25°C. This means at neutral pH, [H⁺] = [OH⁻] = 10⁻⁷ M, giving pH = 7.