Home/
Competitive Exams/
JEE Main & Advanced/
Chemistry/
Chemical and Ionic Equilibrium/
Question 600430
JEE Chemistry · Hard

Chemical and Ionic Equilibrium: Kp from degree of dissociation MCQ

Solve this quality-checked JEE multiple-choice question, then review the correct answer and explanation.

Timer-based practiceDetailed answer reviewMobile-friendly flow
Kp from degree of dissociationHardQuestion 600430

Question

For PCl₅ ⇌ PCl₃ + Cl₂ with degree of dissociation α at pressure P, Kp is:
  1. A
    α²P/(1−α²)
    Correct
  2. B
    α²P/(1+α)
  3. C
    Pα/(1−α²)
  4. D
    Pα²/(1−α)

Correct answer

α²P/(1−α²)

Explanation

Mole fractions: PCl₅ = (1−α)/(1+α), PCl₃ = α/(1+α), Cl₂ = α/(1+α). Kp = [Pα/(1+α)]²/[P(1−α)/(1+α)] = Pα²/(1−α²).

Review Chemical and Ionic Equilibrium notesStart timed chapter practice