OstwaldHardQuestion 600440
Question
Ka of a weak acid HA is 4×10⁻⁵. The degree of dissociation in 0.01 M solution is approximately:
- A2%
- B6.3%Correct
- C20%
- D0.63%
Correct answer
6.3%
Explanation
α = √(Ka/C) = √(4×10⁻⁵/0.01) = √(4×10⁻³) = 0.0632 ≈ 6.3%. The approximation α << 1 holds here (marginally).