JEE Chemistry · Hard

Coordination Compounds: JEE Advanced MCQ

Solve this quality-checked JEE multiple-choice question, then review the correct answer and explanation.

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JEE AdvancedHardQuestion 740012

Question

In [Cr(en)₃]³⁺ (en = ethylenediamine), the hybridisation of Cr is:
  1. A
    d²sp³
    Correct
  2. B
    sp³d²
  3. C
    sp³
  4. D
    dsp²

Correct answer

d²sp³

Explanation

Cr³⁺ is d³. en is a strong field ligand. In octahedral coordination with strong field: inner orbital complex with d²sp³ hybridisation (using 3d, 4s, and 4p orbitals). 3 unpaired electrons remain (t₂g³).