JEE AdvancedHardQuestion 740012
Question
In [Cr(en)₃]³⁺ (en = ethylenediamine), the hybridisation of Cr is:
- Ad²sp³Correct
- Bsp³d²
- Csp³
- Ddsp²
Correct answer
d²sp³
Explanation
Cr³⁺ is d³. en is a strong field ligand. In octahedral coordination with strong field: inner orbital complex with d²sp³ hybridisation (using 3d, 4s, and 4p orbitals). 3 unpaired electrons remain (t₂g³).