JEE Chemistry · Hard

Coordination Compounds: Mixed MCQ

Solve this quality-checked JEE multiple-choice question, then review the correct answer and explanation.

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MixedHardQuestion 740016

Question

CFSE (Crystal Field Stabilisation Energy) for d⁶ in a strong octahedral field (low spin) is:
  1. A
    −2.4Δo
    Correct
  2. B
    −0.4Δo
  3. C
    0
  4. D
    −2.4Δo + 2P (where P = pairing energy)

Correct answer

−2.4Δo

Explanation

Low spin d⁶ in octahedral: t₂g⁶ eg⁰. CFSE = 6×(−0.4Δo) + 0×(+0.6Δo) = −2.4Δo (ignoring pairing energy correction). This high stability is why [Fe(CN)₆]⁴⁻ (Fe²⁺ d⁶, strong CN⁻) is so stable.