JEE Chemistry · Easy

Electrochemistry: Cell EMF MCQ

Solve this quality-checked JEE multiple-choice question, then review the correct answer and explanation.

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Cell EMFEasyQuestion 710004

Question

E°cell = E°cathode − E°anode. For Zn-Cu cell, E°Zn/Zn²⁺ = −0.76 V and E°Cu²⁺/Cu = +0.34 V. E°cell is:
  1. A
    +1.10 V
    Correct
  2. B
    −1.10 V
  3. C
    +0.42 V
  4. D
    −0.42 V

Correct answer

+1.10 V

Explanation

Zn is the anode (oxidised, more negative E°) and Cu is cathode. E°cell = E°cathode − E°anode = 0.34 − (−0.76) = 1.10 V.