Cell EMFEasyQuestion 710004
Question
E°cell = E°cathode − E°anode. For Zn-Cu cell, E°Zn/Zn²⁺ = −0.76 V and E°Cu²⁺/Cu = +0.34 V. E°cell is:
- A+1.10 VCorrect
- B−1.10 V
- C+0.42 V
- D−0.42 V
Correct answer
+1.10 V
Explanation
Zn is the anode (oxidised, more negative E°) and Cu is cathode. E°cell = E°cathode − E°anode = 0.34 − (−0.76) = 1.10 V.