JEE Chemistry · Hard

Electrochemistry: JEE Advanced MCQ

Solve this quality-checked JEE multiple-choice question, then review the correct answer and explanation.

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JEE AdvancedHardQuestion 710014

Question

E°cell for the reaction 2Ag⁺ + H₂ → 2Ag + 2H⁺ at 25°C if E°Ag⁺/Ag = +0.80 V is:
  1. A
    +0.80 V
    Correct
  2. B
    +1.60 V
  3. C
    −0.80 V
  4. D
    0 V

Correct answer

+0.80 V

Explanation

Cathode: Ag⁺ + e⁻ → Ag (E° = +0.80 V). Anode: H₂ → 2H⁺ + 2e⁻ (E° = 0 V). E°cell = 0.80 − 0 = 0.80 V. Note: E° doesn't change when the equation is multiplied.