JEE AdvancedHardQuestion 710014
Question
E°cell for the reaction 2Ag⁺ + H₂ → 2Ag + 2H⁺ at 25°C if E°Ag⁺/Ag = +0.80 V is:
- A+0.80 VCorrect
- B+1.60 V
- C−0.80 V
- D0 V
Correct answer
+0.80 V
Explanation
Cathode: Ag⁺ + e⁻ → Ag (E° = +0.80 V). Anode: H₂ → 2H⁺ + 2e⁻ (E° = 0 V). E°cell = 0.80 − 0 = 0.80 V. Note: E° doesn't change when the equation is multiplied.