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Question 830006
JEE Chemistry · Medium

Haloalkanes and Haloarenes: Elimination MCQ

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EliminationMediumQuestion 830006

Question

Dehydrohalogenation of 2-bromobutane with KOH/ethanol gives the major product:
  1. A
    But-2-ene (more substituted alkene, Zaitsev's rule)
    Correct
  2. B
    But-1-ene (less substituted)
  3. C
    Butane
  4. D
    2-butanol

Correct answer

But-2-ene (more substituted alkene, Zaitsev's rule)

Explanation

E2 elimination follows Zaitsev's rule: the major product is the more substituted (more stable) alkene. From 2-bromobutane: but-2-ene (disubstituted, more stable) > but-1-ene (monosubstituted). Alcoholic KOH provides the base for E2.

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