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Question 830010
JEE Chemistry · Hard

Haloalkanes and Haloarenes: JEE Advanced MCQ

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JEE AdvancedHardQuestion 830010

Question

The Finkelstein reaction converts:
  1. A
    RCl + NaI (in acetone) → RI + NaCl (driving force: insolubility of NaCl)
    Correct
  2. B
    RBr → RCl
  3. C
    Alkene → alkyl halide
  4. D
    Aryl halide → phenol

Correct answer

RCl + NaI (in acetone) → RI + NaCl (driving force: insolubility of NaCl)

Explanation

Finkelstein reaction: alkyl chloride/bromide + NaI in dry acetone → alkyl iodide. NaCl and NaBr are insoluble in acetone and precipitate, driving equilibrium to the right. This is an SN2 exchange reaction.

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