JEE MainHardQuestion 770009
Question
The product of treating propene with HBr in presence of peroxides is:
- A1-bromopropane (anti-Markovnikov)Correct
- B2-bromopropane (Markovnikov)
- CPropane
- DPropyne
Correct answer
1-bromopropane (anti-Markovnikov)
Explanation
Peroxides initiate a free radical chain mechanism. Br• adds to the less substituted end of propene (more stable radical forms at C2). The result is anti-Markovnikov addition: Br goes to C1 → 1-bromopropane. This is the Kharasch effect (peroxide effect).