Home/
Competitive Exams/
JEE Main & Advanced/
Chemistry/
Mole Concept and Stoichiometry/
Question 600013
JEE Chemistry · Medium

Mole Concept and Stoichiometry: Mole–Particle Conversion MCQ

Solve this quality-checked JEE multiple-choice question, then review the correct answer and explanation.

Timer-based practiceDetailed answer reviewMobile-friendly flow
Mole–Particle ConversionMediumQuestion 600013

Question

How many atoms are present in 18 g of water?
  1. A
    6.022 × 10²³
  2. B
    1.806 × 10²⁴
    Correct
  3. C
    3.011 × 10²⁴
  4. D
    1.204 × 10²⁴

Correct answer

1.806 × 10²⁴

Explanation

18 g H₂O = 1 mol H₂O = 6.022×10²³ molecules. Each molecule has 3 atoms (2H + 1O). Total atoms = 3 × 6.022×10²³ = 1.806×10²⁴.

Review Mole Concept and Stoichiometry notesStart timed chapter practice