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Question 600020
JEE Chemistry · Hard

Mole Concept and Stoichiometry: Avogadro Number MCQ

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Avogadro NumberHardQuestion 600020

Question

The number of atoms in 1 g of ⁴He (helium-4) is approximately:
  1. A
    6.022 × 10²³ / 4
  2. B
    6.022 × 10²³ × 4
  3. C
    6.022 × 10²³
  4. D
    1.505 × 10²³
    Correct

Correct answer

1.505 × 10²³

Explanation

n = 1/4 mol. Atoms = (1/4) × 6.022×10²³ = 1.505×10²³. Helium is monatomic, so number of atoms = number of moles × NA.

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