Limiting ReagentMediumQuestion 600031
Question
For 2Al + 3Cl₂ → 2AlCl₃, if 0.3 mol Al and 0.4 mol Cl₂ are mixed, how much AlCl₃ forms?
- A0.267 molCorrect
- B0.3 mol
- C0.4 mol
- D0.2 mol
Correct answer
0.267 mol
Explanation
Al needs: 0.3 × (3/2) = 0.45 mol Cl₂, but only 0.4 mol available → Cl₂ limits. AlCl₃ from Cl₂: 0.4 × (2/3) = 0.267 mol.