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Question 600035
JEE Chemistry · Medium

Mole Concept and Stoichiometry: Molality MCQ

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MolalityMediumQuestion 600035

Question

18 g of glucose (M = 180 g/mol) is dissolved in 90 g of water. The molality of the solution is:
  1. A
    0.1 m
  2. B
    1 m
    Correct
  3. C
    2 m
  4. D
    0.5 m

Correct answer

1 m

Explanation

n(glucose) = 18/180 = 0.1 mol. Solvent = 90 g = 0.09 kg. m = 0.1/0.09 = 1.11 m ≈ 1 m. (Exact: 10/9 ≈ 1.11 m.)

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