JEE Chemistry · Hard

Mole Concept and Stoichiometry: Equivalent Concept MCQ

Solve this quality-checked JEE multiple-choice question, then review the correct answer and explanation.

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Equivalent ConceptHardQuestion 600048

Question

In the reaction: Cr₂O₇²⁻ + Fe²⁺ → Cr³⁺ + Fe³⁺ (acidic medium), the n-factor of K₂Cr₂O₇ is:
  1. A
    2
  2. B
    3
  3. C
    6
    Correct
  4. D
    12

Correct answer

6

Explanation

Each Cr goes from +6 to +3 (change = 3). Two Cr atoms per Cr₂O₇²⁻ → total change = 2×3 = 6. n-factor of K₂Cr₂O₇ = 6.