Home/
Competitive Exams/
JEE Main & Advanced/
Chemistry/
Mole Concept and Stoichiometry/
Question 600056
JEE Chemistry · Hard

Mole Concept and Stoichiometry: Mixture Stoichiometry MCQ

Solve this quality-checked JEE multiple-choice question, then review the correct answer and explanation.

Timer-based practiceDetailed answer reviewMobile-friendly flow
Mixture StoichiometryHardQuestion 600056

Question

A mixture of 0.2 mol Ca and 0.1 mol CaO reacts with water. Moles of Ca(OH)₂ formed are:
  1. A
    0.2 mol
  2. B
    0.3 mol
    Correct
  3. C
    0.1 mol
  4. D
    0.4 mol

Correct answer

0.3 mol

Explanation

Ca + 2H₂O → Ca(OH)₂ + H₂ (0.2 mol Ca → 0.2 mol Ca(OH)₂). CaO + H₂O → Ca(OH)₂ (0.1 mol → 0.1 mol). Total = 0.2 + 0.1 = 0.3 mol Ca(OH)₂.

Review Mole Concept and Stoichiometry notesStart timed chapter practice