JEE Chemistry · Hard

Mole Concept and Stoichiometry: Equivalent Concept MCQ

Solve this quality-checked JEE multiple-choice question, then review the correct answer and explanation.

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Equivalent ConceptHardQuestion 600066

Question

In the disproportionation reaction: Cl₂ + NaOH → NaCl + NaOCl + H₂O. The n-factor of Cl₂ is:
  1. A
    1
    Correct
  2. B
    2
  3. C
    3
  4. D
    0.5

Correct answer

1

Explanation

In disproportionation, Cl₂ (0) → Cl⁻ (−1) and Cl⁰ → Cl⁺¹ (in OCl⁻). Per Cl₂ molecule: one Cl gains 1e⁻, one Cl loses 1e⁻. Net change per mol Cl₂ = 1 (by convention, use the change for reduction or oxidation, not both). n-factor = 1.