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Question 600071
JEE Chemistry · Hard

Mole Concept and Stoichiometry: Equivalent Concept MCQ

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Equivalent ConceptHardQuestion 600071

Question

5.35 g of NH₄Cl (M=53.5 g/mol) is treated with excess NaOH. How many moles of NH₃ are liberated?
  1. A
    0.08 mol
  2. B
    0.1 mol
    Correct
  3. C
    0.12 mol
  4. D
    0.06 mol

Correct answer

0.1 mol

Explanation

n(NH4Cl)=5.35/53.5=0.1n(\mathrm{NH_4Cl})=5.35/53.5=0.1 mol. Because NH4Cl+NaOH→NH3+NaCl+H2O\mathrm{NH_4Cl+NaOH\to NH_3+NaCl+H_2O} is a 1:1 reaction, it liberates 0.1 mol NH₃.

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