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Question 600072
JEE Chemistry · Hard

Mole Concept and Stoichiometry: Combustion Analysis MCQ

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Combustion AnalysisHardQuestion 600072

Question

0.6 g of an organic compound containing C, H, O on combustion gives 0.88 g CO₂ and 0.36 g H₂O. Its empirical formula is:
  1. A
    CH₂O
    Correct
  2. B
    C₂H₄O
  3. C
    CH₄O
  4. D
    C₂H₆O

Correct answer

CH₂O

Explanation

n(C)=0.88/44=0.02 mol, mass C=0.24 g. n(H₂O)=0.36/18=0.02 mol, H=0.04 mol, mass H=0.04 g. O mass=0.6−0.24−0.04=0.32 g → n(O)=0.02 mol. C:H:O = 0.02:0.04:0.02 = 1:2:1 → CH₂O.

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