JEE Chemistry · Medium

Mole Concept and Stoichiometry: Percentage Yield MCQ

Solve this quality-checked JEE multiple-choice question, then review the correct answer and explanation.

Timer-based practiceDetailed answer reviewMobile-friendly flow
Percentage YieldMediumQuestion 600082

Question

Aniline is prepared from nitrobenzene with 75% yield. To get 93 g of aniline (M=93), grams of nitrobenzene (M=123) needed are:
  1. A
    123 g
  2. B
    164 g
    Correct
  3. C
    246 g
  4. D
    82 g

Correct answer

164 g

Explanation

Moles aniline needed = 93/93 = 1 mol. At 75% yield: moles nitrobenzene = 1/0.75 = 1.333 mol. Mass = 1.333 × 123 = 164 g.