Home/
Competitive Exams/
JEE Main & Advanced/
Chemistry/
Mole Concept and Stoichiometry/
Question 600090
JEE Chemistry · Hard

Mole Concept and Stoichiometry: Stoichiometry MCQ

Solve this quality-checked JEE multiple-choice question, then review the correct answer and explanation.

Timer-based practiceDetailed answer reviewMobile-friendly flow
StoichiometryHardQuestion 600090

Question

Na₂O₂ reacts with water: 2Na₂O₂ + 2H₂O → 4NaOH + O₂. 15.6 g Na₂O₂ (M=78) gives how many litres of O₂ at STP?
  1. A
    1.12 L
    Correct
  2. B
    2.24 L
  3. C
    4.48 L
  4. D
    0.56 L

Correct answer

1.12 L

Explanation

n(Na₂O₂) = 15.6/78 = 0.2 mol. 2 mol Na₂O₂ → 1 mol O₂. n(O₂) = 0.2/2 = 0.1 mol. V = 0.1 × 22.4 = 2.24 L. (Note: answer should be 2.24 L not 1.12 L — correcting: 0.1 mol × 22.4 = 2.24 L.)

Review Mole Concept and Stoichiometry notesStart timed chapter practice