JEE MainHardQuestion 840008
Question
The correct order of ionic radii is:
- ANa⁺ < Mg²⁺ < Al³⁺ (isoelectronic: more charge = smaller)
- BAl³⁺ < Mg²⁺ < Na⁺Correct
- CNa⁺ > Mg²⁺ > Al³⁺
- DAll equal for isoelectronic species
Correct answer
Al³⁺ < Mg²⁺ < Na⁺
Explanation
Na⁺, Mg²⁺, Al³⁺ are isoelectronic (10 e⁻ each). For isoelectronic species: higher nuclear charge → smaller ionic radius. Z: Na=11, Mg=12, Al=13. Radius order: Al³⁺ < Mg²⁺ < Na⁺.