Oxidation stateEasyQuestion 700001
Question
The oxidation state of Cr in K₂Cr₂O₇ is:
- A+6Correct
- B+3
- C+7
- D+2
Correct answer
+6
Explanation
K₂Cr₂O₇: 2(+1) + 2x + 7(−2) = 0 → 2 + 2x − 14 = 0 → x = +6.
Solve this quality-checked JEE multiple-choice question, then review the correct answer and explanation.
K₂Cr₂O₇: 2(+1) + 2x + 7(−2) = 0 → 2 + 2x − 14 = 0 → x = +6.