JEE Chemistry · Easy

Redox Reactions: Oxidation state MCQ

Solve this quality-checked JEE multiple-choice question, then review the correct answer and explanation.

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Oxidation stateEasyQuestion 700001

Question

The oxidation state of Cr in K₂Cr₂O₇ is:
  1. A
    +6
    Correct
  2. B
    +3
  3. C
    +7
  4. D
    +2

Correct answer

+6

Explanation

K₂Cr₂O₇: 2(+1) + 2x + 7(−2) = 0 → 2 + 2x − 14 = 0 → x = +6.