Oxidation number changeMediumQuestion 700007
Question
The oxidation state of N in N₂H₄ (hydrazine) is:
- A−2Correct
- B0
- C+2
- D−1
Correct answer
−2
Explanation
N₂H₄: 2x + 4(+1) = 0 → x = −2. Each N is in −2 state.
Solve this quality-checked JEE multiple-choice question, then review the correct answer and explanation.
N₂H₄: 2x + 4(+1) = 0 → x = −2. Each N is in −2 state.