ComproportionationMediumQuestion 700010
Question
In the reaction I₂ + 2S₂O₃²⁻ → 2I⁻ + S₄O₆²⁻, I₂ acts as:
- AOxidising agentCorrect
- BReducing agent
- CBoth
- DNeither
Correct answer
Oxidising agent
Explanation
I in I₂ is 0. In I⁻ it is −1 (gained electrons = reduced). So I₂ is the oxidising agent. S in S₂O₃²⁻ is +2; in S₄O₆²⁻ it is +2.5 (lost electrons = oxidised). So S₂O₃²⁻ is the reducing agent.