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Question 750011
JEE Chemistry · Hard

Solutions and Colligative Properties: JEE Main MCQ

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JEE MainHardQuestion 750011

Question

An aqueous solution of NaCl freezes at −0.744°C. Kf = 1.86 K kg mol⁻¹. The molality of NaCl is:
  1. A
    0.2 m
    Correct
  2. B
    0.4 m
  3. C
    0.1 m
  4. D
    0.744 m

Correct answer

0.2 m

Explanation

ΔTf = i×Kf×m → 0.744 = 2×1.86×m → m = 0.744/3.72 = 0.2 mol/kg.

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