JEE MainHardQuestion 850008
Question
At STP (0°C, 1 atm), 1 mole of an ideal gas occupies:
- A22.4 LCorrect
- B24 L
- C22.4 mL
- D11.2 L
Correct answer
22.4 L
Explanation
Molar volume of ideal gas at STP (0°C = 273 K, 1 atm): V = nRT/P = (1)(0.0821)(273)/1 = 22.4 L. At SATP (25°C, 1 bar), molar volume ≈ 24.8 L.