JEE MainHardQuestion 280010
Question
If the coefficients of x⁷ and x⁸ in (2 + x/3)ⁿ are equal, then n is:
- A55Correct
- B45
- C56
- D35
Correct answer
55
Explanation
Coeff of x⁷: ⁿC₇ 2^(n−7) (1/3)⁷. Coeff of x⁸: ⁿC₈ 2^(n−8) (1/3)⁸. Setting equal: ⁿC₇ × 2/1 = ⁿC₈ × (1/3). 2 ⁿC₇ = ⁿC₈/3. 6ⁿC₇ = ⁿC₈ → 6 = ⁿC₈/ⁿC₇ = (n−7)/8 → n−7 = 48 → n = 55.