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Question 320002
JEE Mathematics · Easy

Circle: Centre and radius MCQ

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Centre and radiusEasyQuestion 320002

Question

For the circle x² + y² − 4x + 6y − 12 = 0, the centre is:
  1. A
    (2, −3)
    Correct
  2. B
    (−2, 3)
  3. C
    (4, −6)
  4. D
    (−4, 6)

Correct answer

(2, −3)

Explanation

General form: x² + y² + 2gx + 2fy + c = 0. Centre = (−g, −f). Here: 2g = −4 → g = −2; 2f = 6 → f = 3. Centre = (2, −3).

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