JEE MainHardQuestion 320009
Question
The equation of circle passing through (0,0), (3,0), and (0,4) is:
- Ax² + y² − 3x − 4y = 0Correct
- Bx²+y²=25
- Cx²+y²−3x−4y+5=0
- D(x−3)²+(y−4)²=25
Correct answer
x² + y² − 3x − 4y = 0
Explanation
General circle: x²+y²+Dx+Ey+F=0. Through (0,0): F=0. Through (3,0): 9+3D=0 → D=−3. Through (0,4): 16+4E=0 → E=−4. Equation: x²+y²−3x−4y=0.