JEE MainHardQuestion 340009
Question
∫₀^π x sin x dx equals:
- AπCorrect
- B0
- C2
- Dπ²
Correct answer
π
Explanation
By parts: ∫₀^π x sin x dx = [−x cos x]₀^π + ∫₀^π cos x dx = (−π cos π + 0) + [sin x]₀^π = π + 0 = π.
Solve this quality-checked JEE multiple-choice question, then review the correct answer and explanation.
By parts: ∫₀^π x sin x dx = [−x cos x]₀^π + ∫₀^π cos x dx = (−π cos π + 0) + [sin x]₀^π = π + 0 = π.