MixedHardQuestion 340015
Question
∫₀^(π/2) sin²x dx equals:
- Aπ/4Correct
- Bπ/2
- C1/2
- D1
Correct answer
π/4
Explanation
sin²x = (1−cos 2x)/2. ∫₀^(π/2) (1−cos 2x)/2 dx = [x/2 − sin 2x/4]₀^(π/2) = (π/4 − 0) − 0 = π/4.
Solve this quality-checked JEE multiple-choice question, then review the correct answer and explanation.
sin²x = (1−cos 2x)/2. ∫₀^(π/2) (1−cos 2x)/2 dx = [x/2 − sin 2x/4]₀^(π/2) = (π/4 − 0) − 0 = π/4.