Differentiability at a pointHardQuestion 360008
Question
f(x) = |x| is not differentiable at x = 0 because:
- ALHD ≠ RHD at x = 0 (−1 ≠ +1)Correct
- Bf(0) is undefined
- Cf is discontinuous at 0
- Df'(0) = ∞
Correct answer
LHD ≠ RHD at x = 0 (−1 ≠ +1)
Explanation
Left derivative: lim(h→0⁻) (|h|−0)/h = −1. Right derivative: lim(h→0⁺) h/h = +1. LHD ≠ RHD → not differentiable at x = 0 (though f is continuous there).