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Question 400009
JEE Mathematics · Hard

Ellipse and Hyperbola: JEE Advanced MCQ

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JEE AdvancedHardQuestion 400009

Question

For a hyperbola x²/9 − y²/16 = 1, the asymptotes are:
  1. A
    y = ±(4/3)x
    Correct
  2. B
    y = ±(3/4)x
  3. C
    y = ±4x
  4. D
    y = ±3x

Correct answer

y = ±(4/3)x

Explanation

Asymptotes of x²/a²−y²/b²=1: y = ±(b/a)x. Here a²=9 (a=3), b²=16 (b=4). Asymptotes: y = ±(4/3)x.

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