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Question 400011
JEE Mathematics · Medium

Ellipse and Hyperbola: Mixed MCQ

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MixedMediumQuestion 400011

Question

The eccentricity of x²/16 − y²/9 = 1 is:
  1. A
    5/4
    Correct
  2. B
    3/4
  3. C
    4/3
  4. D
    5/3

Correct answer

5/4

Explanation

a² = 16, b² = 9 (hyperbola). c² = a² + b² = 25 → c = 5. e = c/a = 5/4 > 1 (confirming hyperbola).

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