Partial fractionsMediumQuestion 330006
Question
∫1/(x²−1) dx using partial fractions gives:
- A(1/2)ln|(x−1)/(x+1)| + CCorrect
- Bln|x²−1| + C
- C1/(x²−1) + C
- D(1/2)ln|x+1|/(x−1)| + C
Correct answer
(1/2)ln|(x−1)/(x+1)| + C
Explanation
1/(x²−1) = 1/((x−1)(x+1)) = (1/2)[1/(x−1) − 1/(x+1)]. Integrating: (1/2)[ln|x−1| − ln|x+1|] = (1/2)ln|(x−1)/(x+1)| + C.