Quadratic inequality parameterHardQuestion 220021
Question
x² − (a+b)x + ab < 0 where a < b. Solution:
- Aa < x < bCorrect
- Bx < a or x > b
- Cx < 0
- Da ≤ x ≤ b
Correct answer
a < x < b
Explanation
x² − (a+b)x + ab = (x−a)(x−b). Since a < b, this is negative between the roots: a < x < b.