Sum of squaresMediumQuestion 210021
Question
The sum 1² + 2² + 3² + ... + n² equals:
- An(n+1)/2
- Bn(n+1)(2n+1)/6Correct
- C[n(n+1)/2]²
- Dn(n+1)(n+2)/6
Correct answer
n(n+1)(2n+1)/6
Explanation
Sum of squares of first n natural numbers = n(n+1)(2n+1)/6. For n=3: 1+4+9 = 14 = 3×4×7/6 = 84/6 = 14 ✓.