Integer sumHardQuestion 210035
Question
How many terms of the AP 1, 4, 7, ... are needed for the sum to first exceed 500?
- A18Correct
- B19
- C17
- D20
Correct answer
18
Explanation
Sₙ = n(2 + (n−1)3)/2 = n(3n−1)/2 > 500. So 3n²−n > 1000. Testing n=18: 3(324)−18 = 972−18 = 954 > 1000? No: 954/2 = 477. n=19: 3(361)−19 = 1083−19=1064; 1064/2 = 532 > 500. So n = 19.