Distance from point to planeHardQuestion 350008
Question
The distance from point (x₁,y₁,z₁) to plane ax+by+cz+d=0 is:
- A|ax₁+by₁+cz₁+d|/√(a²+b²+c²)Correct
- B(ax₁+by₁+cz₁+d)/(a+b+c)
- C|ax₁+by₁+cz₁|/√(a²+b²+c²)
- D√(a²+b²+c²)
Correct answer
|ax₁+by₁+cz₁+d|/√(a²+b²+c²)
Explanation
Distance = |ax₁+by₁+cz₁+d| / √(a²+b²+c²). This is analogous to the 2D formula |ax₁+by₁+c|/√(a²+b²).